Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A ball is projected from the ground with velocity
such that its range is maximum
Column I | Column II | ||
(A) | Velocity at half of the maximum height | (I) | |
(B) | Velocity at the maximum height | (II) | |
(C) | Change in its velocity when it returns to the ground | (III) | |
(D) | Average velocity when it reaches the maximum height | (IV) |
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: For a projectile launched at an angle, the velocity can be broken into two components: horizontal and vertical. The maximum height occurs when the vertical component of the velocity is zero.
Step 2: At maximum height, the velocity is only the horizontal component which remains constant throughout the flight.
Step 3: At half the maximum height, the vertical component has decreased, and the total velocity can be calculated using the components.
Step 4: When the ball returns to the ground, the change in velocity is equal to the initial velocity vector. Thus:
Therefore, the correct mapping is A-I, B-II, C-III, D-IV.
Step 2: At maximum height, the velocity is only the horizontal component which remains constant throughout the flight.
Step 3: At half the maximum height, the vertical component has decreased, and the total velocity can be calculated using the components.
Step 4: When the ball returns to the ground, the change in velocity is equal to the initial velocity vector. Thus:
- A corresponds to I (Velocity at half of the maximum height is
). - B corresponds to II (Velocity at the maximum height is the horizontal component only).
- C corresponds to III (Change in its velocity when it returns to the ground is equal to the initial launch velocity).
- D corresponds to IV (Average velocity when it reaches maximum height is half the initial velocity).
Therefore, the correct mapping is A-I, B-II, C-III, D-IV.
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